\(\int (a+a \sin (c+d x))^{4/3} \, dx\) [101]

Optimal result

Integrand size = 14, antiderivative size = 67 \[ \int (a+a \sin (c+d x))^{4/3} \, dx=-\frac {2\ 2^{5/6} a \cos (c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {5}{6},\frac {1}{2},\frac {3}{2},\frac {1}{2} (1-\sin (c+d x))\right ) \sqrt [3]{a+a \sin (c+d x)}}{d (1+\sin (c+d x))^{5/6}} \]

[Out]

-2*2^(5/6)*a*cos(d*x+c)*hypergeom([-5/6, 1/2],[3/2],1/2-1/2*sin(d*x+c))*(a+a*sin(d*x+c))^(1/3)/d/(1+sin(d*x+c)
)^(5/6)

Rubi [A] (verified)

Time = 0.02 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2731, 2730} \[ \int (a+a \sin (c+d x))^{4/3} \, dx=-\frac {2\ 2^{5/6} a \cos (c+d x) \sqrt [3]{a \sin (c+d x)+a} \operatorname {Hypergeometric2F1}\left (-\frac {5}{6},\frac {1}{2},\frac {3}{2},\frac {1}{2} (1-\sin (c+d x))\right )}{d (\sin (c+d x)+1)^{5/6}} \]

[In]

Int[(a + a*Sin[c + d*x])^(4/3),x]

[Out]

(-2*2^(5/6)*a*Cos[c + d*x]*Hypergeometric2F1[-5/6, 1/2, 3/2, (1 - Sin[c + d*x])/2]*(a + a*Sin[c + d*x])^(1/3))
/(d*(1 + Sin[c + d*x])^(5/6))

Rule 2730

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(-2^(n + 1/2))*a^(n - 1/2)*b*(Cos[c + d*x]/
(d*Sqrt[a + b*Sin[c + d*x]]))*Hypergeometric2F1[1/2, 1/2 - n, 3/2, (1/2)*(1 - b*(Sin[c + d*x]/a))], x] /; Free
Q[{a, b, c, d, n}, x] && EqQ[a^2 - b^2, 0] &&  !IntegerQ[2*n] && GtQ[a, 0]

Rule 2731

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Dist[a^IntPart[n]*((a + b*Sin[c + d*x])^FracPart
[n]/(1 + (b/a)*Sin[c + d*x])^FracPart[n]), Int[(1 + (b/a)*Sin[c + d*x])^n, x], x] /; FreeQ[{a, b, c, d, n}, x]
&& EqQ[a^2 - b^2, 0] &&  !IntegerQ[2*n] &&  !GtQ[a, 0]

Rubi steps \begin{align*} \text {integral}& = \frac {\left (a \sqrt [3]{a+a \sin (c+d x)}\right ) \int (1+\sin (c+d x))^{4/3} \, dx}{\sqrt [3]{1+\sin (c+d x)}} \\ & = -\frac {2\ 2^{5/6} a \cos (c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {5}{6},\frac {1}{2},\frac {3}{2},\frac {1}{2} (1-\sin (c+d x))\right ) \sqrt [3]{a+a \sin (c+d x)}}{d (1+\sin (c+d x))^{5/6}} \\ \end{align*}

Mathematica [B] (verified)

Leaf count is larger than twice the leaf count of optimal. \(223\) vs. \(2(67)=134\).

Time = 0.99 (sec) , antiderivative size = 223, normalized size of antiderivative = 3.33 \[ \int (a+a \sin (c+d x))^{4/3} \, dx=\frac {(a (1+\sin (c+d x)))^{4/3} \left (20 \sqrt [3]{2} \cos \left (\frac {1}{4} (2 c+\pi +2 d x)\right ) \, _2F_1\left (-\frac {1}{2},-\frac {1}{6};\frac {5}{6};\sin ^2\left (\frac {1}{4} (2 c+\pi +2 d x)\right )\right )-\sqrt {2-2 \sin (c+d x)} \left (10 \sqrt [3]{2} \cos \left (\frac {1}{4} (2 c+\pi +2 d x)\right )+3 \cos (c+d x) \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^{2/3} \sqrt [3]{\sin \left (\frac {1}{4} (2 c+\pi +2 d x)\right )}\right )\right )}{8 d \sqrt {\cos ^2\left (\frac {1}{4} (2 c+\pi +2 d x)\right )} \left (\cos \left (\frac {1}{2} (c+d x)\right )+\sin \left (\frac {1}{2} (c+d x)\right )\right )^{8/3} \sqrt [3]{\sin \left (\frac {1}{4} (2 c+\pi +2 d x)\right )}} \]

[In]

Integrate[(a + a*Sin[c + d*x])^(4/3),x]

[Out]

((a*(1 + Sin[c + d*x]))^(4/3)*(20*2^(1/3)*Cos[(2*c + Pi + 2*d*x)/4]*HypergeometricPFQ[{-1/2, -1/6}, {5/6}, Sin
[(2*c + Pi + 2*d*x)/4]^2] - Sqrt[2 - 2*Sin[c + d*x]]*(10*2^(1/3)*Cos[(2*c + Pi + 2*d*x)/4] + 3*Cos[c + d*x]*(C
os[(c + d*x)/2] + Sin[(c + d*x)/2])^(2/3)*Sin[(2*c + Pi + 2*d*x)/4]^(1/3))))/(8*d*Sqrt[Cos[(2*c + Pi + 2*d*x)/
4]^2]*(Cos[(c + d*x)/2] + Sin[(c + d*x)/2])^(8/3)*Sin[(2*c + Pi + 2*d*x)/4]^(1/3))

Maple [F]

\[\int \left (a +a \sin \left (d x +c \right )\right )^{\frac {4}{3}}d x\]

[In]

int((a+a*sin(d*x+c))^(4/3),x)

[Out]

int((a+a*sin(d*x+c))^(4/3),x)

Fricas [F]

\[ \int (a+a \sin (c+d x))^{4/3} \, dx=\int { {\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {4}{3}} \,d x } \]

[In]

integrate((a+a*sin(d*x+c))^(4/3),x, algorithm="fricas")

[Out]

integral((a*sin(d*x + c) + a)^(4/3), x)

Sympy [F]

\[ \int (a+a \sin (c+d x))^{4/3} \, dx=\int \left (a \sin {\left (c + d x \right )} + a\right )^{\frac {4}{3}}\, dx \]

[In]

integrate((a+a*sin(d*x+c))**(4/3),x)

[Out]

Integral((a*sin(c + d*x) + a)**(4/3), x)

Maxima [F]

\[ \int (a+a \sin (c+d x))^{4/3} \, dx=\int { {\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {4}{3}} \,d x } \]

[In]

integrate((a+a*sin(d*x+c))^(4/3),x, algorithm="maxima")

[Out]

integrate((a*sin(d*x + c) + a)^(4/3), x)

Giac [F]

\[ \int (a+a \sin (c+d x))^{4/3} \, dx=\int { {\left (a \sin \left (d x + c\right ) + a\right )}^{\frac {4}{3}} \,d x } \]

[In]

integrate((a+a*sin(d*x+c))^(4/3),x, algorithm="giac")

[Out]

integrate((a*sin(d*x + c) + a)^(4/3), x)

Mupad [F(-1)]

Timed out. \[ \int (a+a \sin (c+d x))^{4/3} \, dx=\int {\left (a+a\,\sin \left (c+d\,x\right )\right )}^{4/3} \,d x \]

[In]

int((a + a*sin(c + d*x))^(4/3),x)

[Out]

int((a + a*sin(c + d*x))^(4/3), x)